Mathematics
19 Online
OpenStudy (anonymous):
Need help on rectangular distribution
A random variable, X, has the pdf:
f(x) = 0.05, 0
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[0 \le x \le 20\]
OpenStudy (anonymous):
instead of 0 < x < 20
OpenStudy (zarkon):
< or \(\le\)...it doesn't matter
OpenStudy (anonymous):
I've drawn the rectangular distribution graph but got the answer to the first one wrong
OpenStudy (zarkon):
what did you get for an answer?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Sorry, I meant I got the second one wrong
OpenStudy (anonymous):
Just realized I got the first one right
OpenStudy (zarkon):
if you can do (a) you should be able to do (b)
OpenStudy (anonymous):
I got 0.61 for some reason for b
OpenStudy (zarkon):
and how did you get that?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
20-7.8/20-0
OpenStudy (zarkon):
7.8/20
OpenStudy (anonymous):
Oh is it 7.8-0/20-0?
OpenStudy (zarkon):
you should use parentheses
OpenStudy (anonymous):
For what?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So like (7.8-0)/(20-0)?
OpenStudy (zarkon):
7.8-0/20-0=7.8-0-0=7.8
(7.8-0)/(20-0)=\(\dfrac{7.8}{20}=.39\)
OpenStudy (anonymous):
I see, so how do I go about doing the 3c?
OpenStudy (zarkon):
\[P(a<x<b)=\frac{b-a}{20}\]
for \(0\le a,b\le 20\)
OpenStudy (anonymous):
Thanks
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I got it right
OpenStudy (zarkon):
good