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Mathematics 17 Online
OpenStudy (anonymous):

if y=45 when x=270, what is y when x=252?

OpenStudy (anonymous):

Is this a direct variation? Again, this is a problem which is not clear in the wording.

OpenStudy (ness9630):

It's a direct variation, so use: y=kx You have 45=270k Solve for k Once that's done, plug it back in to get the next y

OpenStudy (anonymous):

How do you know this is a direct variation?????????

OpenStudy (anonymous):

Why are you assuming that it is a direct variation problem if it doesnt say so. Perhaps this is an inverse variation problem. Who knows? Nobody know unless it says so in the stem.

OpenStudy (anonymous):

the problem does not say anything just that what I asked, so im guessing the problem is inaccurate.

OpenStudy (zale101):

what chapter are u learning andrew?

OpenStudy (anonymous):

Tell your teacher that you dont know how x and y vary, thus you cannot answer the question.

OpenStudy (ness9630):

That's true, but if it wanted you to know it was an inverse variation, it would of let you know.

OpenStudy (ness9630):

I've been doing this long enough to know.

OpenStudy (anonymous):

Not if this is a problem in the section of Inverse Variations.

OpenStudy (anonymous):

there is one heading in bold on this page and says " Find the value of y for a given value of x, if y varies directly with x" Not sure if it goes with that question but doesn't say aswell. should I assume its direct?

OpenStudy (anonymous):

Ness..take my word, I've been with this longer than you have, and when a question is ambiguous, the question is to be tossed.

OpenStudy (zale101):

yeah, so ur question is trying to find the direct variation

OpenStudy (ness9630):

Told ya ;)

OpenStudy (anonymous):

OK, if it says direct variation, then it is direct variation!

OpenStudy (anonymous):

ness9630 if the question is direct, where does the k come from? I got k=0.16 but there is no k even in the question nor a problem to plug it into

OpenStudy (anonymous):

Ness...that's not a valid argument...told you so..sounds childish to me. If you are an educator, you would know better than that.

OpenStudy (zale101):

how about u guys stop arguing and let's find a way to help @andrewc98

OpenStudy (ness9630):

Classic zale

OpenStudy (zale101):

@andrewc98 the form of finding the direct variation is y=kx and the form of finding the inverse variation is y=k/x

OpenStudy (zale101):

but your question is looking for the direct variation

OpenStudy (zale101):

k is the constant variation

OpenStudy (ness9630):

Once you know k, plug it back in to y=kx with the new given value

OpenStudy (zale101):

If y varies directly as x, and y = to something when x = something, then it's asked to find k

OpenStudy (anonymous):

okay I did the math and the answer k=0.16 is not correct. 0.16*252 to find y is 40.32 but there is no 40.32 there is a.-1512 b.1512 c-42 d.42

OpenStudy (ness9630):

So y=(252)k Plug your value of k back in.

OpenStudy (ness9630):

Your math is wrong

OpenStudy (anonymous):

i rearranged the numbers 45*270 and got 1512 which is an answer choice so i guess ill go with that.

OpenStudy (ness9630):

So 45/270 simplifies to 1/6 and 1/6*252 252/6=?

OpenStudy (anonymous):

Thank you all for helping me, i appreciate it!

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