if y=45 when x=270, what is y when x=252?
Is this a direct variation? Again, this is a problem which is not clear in the wording.
It's a direct variation, so use: y=kx You have 45=270k Solve for k Once that's done, plug it back in to get the next y
How do you know this is a direct variation?????????
Why are you assuming that it is a direct variation problem if it doesnt say so. Perhaps this is an inverse variation problem. Who knows? Nobody know unless it says so in the stem.
the problem does not say anything just that what I asked, so im guessing the problem is inaccurate.
what chapter are u learning andrew?
Tell your teacher that you dont know how x and y vary, thus you cannot answer the question.
That's true, but if it wanted you to know it was an inverse variation, it would of let you know.
I've been doing this long enough to know.
Not if this is a problem in the section of Inverse Variations.
there is one heading in bold on this page and says " Find the value of y for a given value of x, if y varies directly with x" Not sure if it goes with that question but doesn't say aswell. should I assume its direct?
Ness..take my word, I've been with this longer than you have, and when a question is ambiguous, the question is to be tossed.
yeah, so ur question is trying to find the direct variation
Told ya ;)
OK, if it says direct variation, then it is direct variation!
ness9630 if the question is direct, where does the k come from? I got k=0.16 but there is no k even in the question nor a problem to plug it into
Ness...that's not a valid argument...told you so..sounds childish to me. If you are an educator, you would know better than that.
how about u guys stop arguing and let's find a way to help @andrewc98
Classic zale
@andrewc98 the form of finding the direct variation is y=kx and the form of finding the inverse variation is y=k/x
but your question is looking for the direct variation
k is the constant variation
Once you know k, plug it back in to y=kx with the new given value
If y varies directly as x, and y = to something when x = something, then it's asked to find k
okay I did the math and the answer k=0.16 is not correct. 0.16*252 to find y is 40.32 but there is no 40.32 there is a.-1512 b.1512 c-42 d.42
So y=(252)k Plug your value of k back in.
Your math is wrong
i rearranged the numbers 45*270 and got 1512 which is an answer choice so i guess ill go with that.
So 45/270 simplifies to 1/6 and 1/6*252 252/6=?
Thank you all for helping me, i appreciate it!
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