why doesn't the unit for curvature have a theta somewhere?
@mathslover
Sorry, I have not studied that yet. @hartnn - may help you.
thanks for knowing who to go to
That's my work :)
why should it have it ? its just reciprocal of distance ? so m^-1 ?
The curvature of a circle of radius r is 1/r. In other words, if you expand a circle by a factor of k, then its curvature shrinks by a factor of k. So the units of curvature is just inverse-length.
Smaller circles bend more sharply, and hence have higher curvature
so it isn't change in angle with respect to distance along the curve
do you mean to say about Angular displacement?
yeah, thats ang displ. unit: radians/m it will have dimensions of theta
Okay!
so how does curvature relate to angular displacement? or are they completely unrelated?
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