why doesn't the unit for curvature have a theta somewhere?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@mathslover
mathslover (mathslover):
Sorry, I have not studied that yet. @hartnn - may help you.
OpenStudy (anonymous):
thanks for knowing who to go to
mathslover (mathslover):
That's my work :)
hartnn (hartnn):
why should it have it ? its just reciprocal of distance ? so m^-1 ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
The curvature of a circle of radius r is 1/r. In other words, if you expand a circle by a factor of k, then its curvature shrinks by a factor of k. So the units of curvature is just inverse-length.
hartnn (hartnn):
Smaller circles bend more sharply, and hence have higher curvature
OpenStudy (anonymous):
so it isn't change in angle with respect to distance along the curve
mathslover (mathslover):
do you mean to say about Angular displacement?
hartnn (hartnn):
yeah, thats ang displ.
unit: radians/m
it will have dimensions of theta
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
mathslover (mathslover):
Okay!
OpenStudy (anonymous):
so how does curvature relate to angular displacement? or are they completely unrelated?