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Mathematics 20 Online
OpenStudy (anonymous):

why doesn't the unit for curvature have a theta somewhere?

OpenStudy (anonymous):

@mathslover

mathslover (mathslover):

Sorry, I have not studied that yet. @hartnn - may help you.

OpenStudy (anonymous):

thanks for knowing who to go to

mathslover (mathslover):

That's my work :)

hartnn (hartnn):

why should it have it ? its just reciprocal of distance ? so m^-1 ?

hartnn (hartnn):

The curvature of a circle of radius r is 1/r. In other words, if you expand a circle by a factor of k, then its curvature shrinks by a factor of k. So the units of curvature is just inverse-length.

hartnn (hartnn):

Smaller circles bend more sharply, and hence have higher curvature

OpenStudy (anonymous):

so it isn't change in angle with respect to distance along the curve

mathslover (mathslover):

do you mean to say about Angular displacement?

hartnn (hartnn):

yeah, thats ang displ. unit: radians/m it will have dimensions of theta

mathslover (mathslover):

Okay!

OpenStudy (anonymous):

so how does curvature relate to angular displacement? or are they completely unrelated?

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