it is a conceptual problem, just plug in infinity... what was the original problem?
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OpenStudy (anonymous):
@jigglypuff314 the original problem is in the attachment. yeah but i plugged in and i get (-infinity)/(infinity) right?
jigglypuff314 (jigglypuff314):
yes, but when dividing infinities, which is the bigger infinity?
OpenStudy (anonymous):
what do u mean? is there any bigger than infinity? haha xD, i have no idea how to get -1/2. thats the answer
jigglypuff314 (jigglypuff314):
on top is -(infinity + (number that can be ignored))
over (√(infinity^2) + √(infinity^2)) = infinity + infinity
so -(infinity)/(2infinity) the infinities cancel out and you're left with -1/2
OpenStudy (anonymous):
ohh.. infinities can cancel out haha, i see, thanks! i always get this thinking that you cnnot do minus and divide on infinities..omgg thank you!! :D
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