Question

the table shows frequecies for red-green color blindness in doctor's practive. M is male C is Person is color-blind. Use this table to find the probabilit P(C) C & M 0.045 C&M' 0.002 Totals: 0.047 C'&M 0.463 C'&M' 0.490 Totals:0.953 Totals M:0.508 M' 0.492 Total:1.000 Use this table to find the probability P( M' intersection C') .. can you help me out please?

Answer 1

It's hard to understand the frequency table. Maybe if you drew it typed it into a table.

Answer 2

1 MIN

Answer 3

M M' Totals
C 0.045 0.002 0.047
C' 0.463 0.490 0.953
Totals 0.508 0.492 1.000

the table shows frequecies for red-green color blindness in doctor's practive. M is male C is Person is color-blind. Use this table to find the probability P(M' intersection C')

Answer 4

is it clear now
?

Answer 5

yes

Answer 6

is it 0.490/0.492 ?

Answer 7

Each entry indicates the probability of the row/column element. For \(C'\cap M'\), we go to column M' and row C' and find the entry there.

Answer 8

ok

Answer 9

If you wanted to find Probability of M' AND C' GIVEN M', then you would use the formula you wrote above.

Answer 10

so can we say given C' is 0.490 M' is 0.454 thus, result is is 0.490/0.454 ?

Answer 11

sorry 0.490 /0.492 ?

Answer 12

The right way to write this is \(P(C'\cap M'|~M')=\cfrac{P(C'\cap M')}{P(M')}=\cfrac{.490}{.492}\)

Answer 13

ohh thats perfect thanks

Answer 14

NP

Answer 15

do u have time ..if as you other one

Answer 16

ok

Answer 17

this is my first day.. learning here

Answer 18

I see that

Answer 19

m m' total
c 0.042 0.003 0.045
c' 0.398 0.557 0.955
total 0.44 0.56 1.000
the table shows frequecies for red-green color blindness in doctor's practive. M is male C is Person is color-blind. Use this table to find the probability P(C' I M')

Answer 20

\(P(C'|M')=\cfrac{P(C'\cap M')}{P(M')}=\cfrac{.557}{.56}\), using Baye's Theorem.

Answer 21

thanks

Answer 22

for two events, M and N , P(M)=0.4 P(N I M)=0.6, And p(N I M')=0.3 Find P( M' I N) =?

Answer 23

$$
N=\{\{M|N\}\cup \{M'|N\}\}\\
P(M'|N)=1-P(M|N)\\
P(M|N)=\cfrac{P(M\cap N)}{P(N)}=\cfrac{P(N| M)P(M)}{P(N)}\\
$$
Now, just plug in your givens to solve.

Answer 24

thnks