What is the equation of the line that passes through ( 1,5) and (4,11)?
do you know what the equation for a line is?
np
What is the equation of the line that passes through ( 1,5) and (4,11)? Select one: a. y = 6 b. y = x + 2 c. y = 2x + 3 d. y = 3x + 4
ok so what is the basic equation for any line
y= bx+m
or is it the other way around y= mx +b
that is exactly right so do you know how what m is and how to calculate it
is it the slope ?? and no
ok so you are right it is the slope, so you calculate it with the following formulae: \[m=\frac{ (y2-y1) }{ (x2-x1) }\] I this may look complex but all but (x,y) is simply a coordinate so x1 is the x value of the first coordinate y 1 is the y value of the first coordinate
First find the slope of the line: \[\LARGE \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\] with \[\LARGE (x_{1}, y_{1});(x_{2}, y_{2})\]
Once you fond the slope, use the equation: \[\LARGE y-y_{1}=m(x-x_{1})\] Where m=slope
Then after using the point-slope formula get it into slope-intercept form: \[\LARGE y=mx+b\]
sooo from the answr choices earlier the answer is A
What is the equation of the line that passes through ( 1,5) and (4,11)? Select one: a. y = 6 b. y = x + 2 c. y = 2x + 3 d. y = 3x + 4
We're not here to give you answers, we are here to guide you towards it
NUT I DONT KNOW IT
BUT
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