Question

please help-
what is the inverse of
sq root (x) + 1

Answer 1

Your original equation:\[y = \sqrt{x+1}\]
we swap "x" and "y" to get:\[x = \sqrt{y+1}\]now square both sides to get rid of the "square root"\[x^2 = y +1\]subtract 1 from both sides \[y = x^2 -1\] does that answer your question?

Answer 2

or is your original equation \[y =\sqrt{x} +1 ?\]

Answer 3

If my last statement is true, the new inverse would to solve for "x" then do the swap. which follows as so:

Subtract one from both sides:\[y -1 = \sqrt{x}\]
square both sides:\[(y-1)^2 = x\]
swap "x" and "y" to get the final equation:
\[y = (x-1)^2\]