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Mathematics 7 Online
OpenStudy (anonymous):

Please help if you're fairly good in algebra 2 medals will b awarded :) whats the solution set to the given inequality? |x + 3| < 12

OpenStudy (anonymous):

yess hold on

OpenStudy (anonymous):

(-infinity, -15) U (9, infin)

OpenStudy (anonymous):

(-infinity, -5) upside down U (9, infinity)

OpenStudy (anonymous):

[-15,9]

OpenStudy (anonymous):

(-15,9)

OpenStudy (anonymous):

a,b,c,d those are the options

hartnn (hartnn):

|a| < b gives you a< b or a>-b (or equivalently -b<a<b) so what about |x+3| < 12 ?

OpenStudy (anonymous):

so is correct?

OpenStudy (anonymous):

b

OpenStudy (anonymous):

(=infin, -15) upsidedown U (9, infin)

hartnn (hartnn):

why upsiddown U ?

OpenStudy (anonymous):

oh wait it a union right?

OpenStudy (anonymous):

so reg U

hartnn (hartnn):

no, its not the first choice either

hartnn (hartnn):

x+3<12 gives you x<9 right ?

OpenStudy (anonymous):

ugh :(

OpenStudy (anonymous):

yess.

hartnn (hartnn):

good, and x+3 > -12 gives you x>-15 this ?

OpenStudy (anonymous):

agree

hartnn (hartnn):

so x is between -15 and 9, right ? so (-15,9)

OpenStudy (anonymous):

ohhhh.. i think im starting to understand it more :D

hartnn (hartnn):

i am glad to hear that! :)

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