Question

Please help if you're fairly good in algebra 2 medals will b awarded :)
whats the solution set to the given inequality?
|x + 3| < 12

Answer 1

yess hold on

Answer 2

(-infinity, -15) U (9, infin)

Answer 3

(-infinity, -5) upside down U (9, infinity)

Answer 4

[-15,9]

Answer 5

(-15,9)

Answer 6

a,b,c,d those are the options

Answer 7

|a| < b gives you
a< b or a>-b (or equivalently -b<a<b)

so what about |x+3| < 12 ?

Answer 8

so is correct?

Answer 9

b

Answer 10

(=infin, -15) upsidedown U (9, infin)

Answer 11

why upsiddown U ?

Answer 12

oh wait it a union right?

Answer 13

so reg U

Answer 14

no, its not the first choice either

Answer 15

x+3<12
gives you x<9 right ?

Answer 16

ugh :(

Answer 17

yess.

Answer 18

good, and x+3 > -12 gives you
x>-15
this ?

Answer 19

agree

Answer 20

so x is between -15 and 9, right ?
so (-15,9)

Answer 21

ohhhh.. i think im starting to understand it more :D

Answer 22

i am glad to hear that! :)