Question

Need help finding the area! Please help!!!


4.Examine the figure below and answer the questions that follow. Be sure to write your answers in standard form and write the degree and classification for each answer.

Answer 1

I haven't seen anything like this and really need help.

Answer 2

a.Create the expression that represents the area of the wall space only using the dimensions shown above. Show your work.

b.The contractor is trying to design a scale model of the wall to show the buildings manager. To create this scale, he will have to divide the the area of the wall as calculated in Part A by 4xy4. With the polynomial in standard form, divide the first term only by 4xy4. Then divide the second term only by 4xy4. Show your work for the division of each term by 4xy4 separately.

c.If a wall with the area of 12xy4 was placed on this wall, what would be the new area of the wall space left? You must show all work and calculations to receive credit.

Answer 3

For a, is it (5x^2y^3)^3 (4y^2)^3 - (4y^4) (3x)

Answer 4

for part a that is correct :)

Answer 5

Can you help me simplify the area from part a ? @jigglypuff314

Answer 6

I am not sure if what I got was right but here is what I did:
(5x^2y^3)^3 (4y^2)^3 - (4y^4) (3x) distribute the exponents
(5^3 * x^(2*3) * y^(3*3))(4^3 * y^(2*3)) - (4*3*x*y^4) then simplify
(125*x^6*y^9)(64*y^6) - (12*x*y^4)
8000*x^6*y^15 - 12*x*y^4

Answer 7

8,000x^6y^15 -12xy^4

for part b, it said to divide both terms by 4xy^4 separately.

So how do I divide 8,000x^6y^15 / 4xy^4
AND -12xy^4 (not sure if the 12 is supposed to be negative or not but I think so)

@jigglypuff314

Answer 8

remember that when dividing exponents you subtract so...
x^6/x = x^(6-1)
and y^15/y^4 = y^(15-4)

Answer 9

So is it 2,000x^5y^11-3 ? @jigglypuff314

Answer 10

yes :)

Answer 11

thank you!
Now c?

Answer 12

no clue :/

Answer 13

the area that would be left would be (2000x^5y^11 - 3) - 12xy^4

Answer 14

wouldn't I be adding the 12xy^4? @jigglypuff314

"If a wall with the area of 12xy4 was placed on this wall, what would be the new area of the wall space left?"

Answer 15

wouldn't it just be filling in the hole that was cut out for a door?

Answer 16

sorry, I'm bad with word problems...
the new wall is the same area as the hole in the previous wall so the new area would be
8000x^6y^15 so yeah :P

Answer 17

Thank you so much! You really helped me a lot!

Answer 18

Wait! one more question,.. to get that answer would I do
2,000x^5y^11 * 12xy^4 - (-3 * 12xy^4) ? @jigglypuff314

Answer 19

i have to show my work

Answer 20

or is it 2,000x^5y^11 * 12xy^4 * (-3 * 12xy^4)

Answer 21

where did the -3 come from ^ ?

Answer 22

Because for part b the answer was 2,000x^5y^11-3

Answer 23

hmm, by "this wall" in part c, is it referring to the model wall or the original wall?

Answer 24

because if it was the original wall then (5x^2y^3)^3 * (4y^2)^3

Answer 25

okay you know how it has a part cut ou for the door? well basically another wall was created that's fits in the hole perfectly, and it wants to know the area now that there is no hole.

Answer 26

so are you using the area you got from part a or part b?

Answer 27

Wait i think I got it! Okay so to begin with, to find the area to equation was
8,000x^6y^15 -12xy^4
but now you add the -12xy^4 on both sides
dooes this sound about right or am I completely off? @jigglypuff314

Answer 28

8,000x^6y^15 -12xy^4 is the area with the hole + 12xy^4 to fill the hole
-12xy^4 + 12xy^4 = 0 so you are left with 8,000x^6y^15 as the area

Answer 29

would i add 12xy^4 to both sides?
i would think so... right?

Answer 30

I'm not quite sure I understand what you mean by "both sides"

Answer 31

8000X^6Y^15 -12XY^4
+12XY^4 +12XY^4

LIKE THAT ^?

Answer 32

no, wait, no... you only need to add the 12xy^4 once

Answer 33

Oh okay thanks!!!