Question

How can I integrate 1/x from -1 to 1?

I know that it is unbounded integrand because there is an asymptote at x = 0. So I am confused on how to do this from -1 to 1

Answer 1

Integral of 1/x dx = ln abs( x)
Now you need to use improper integrals to continue becuase of the problem you stated.

Answer 2

How do I do this?

Answer 3

Hint: break up from -1 to 0 and then from 0 to 1..and take their limits.

Answer 4

Is the answer 0?

Answer 5

I got lim a-> 0 of ln|a| - ln|a|, which is lim a-> 0 of 0, so result is 0?