**PLEASE HELP! FAN AND MEDAL!!!** 4/5x + 4/3 = 2x solve for X
4/(5x) + 4/3 = 2x
multiply both sides by (5x)(3) so you get 4(3) + 4(5x) = (2x)(5x)(3) simplify 12 + 20x = 30x^2 bring all the values to one side 30x^2 - 20x - 12 = 0 then factor out greatest common factor and factor.
multiply every term by 15x this wll eliminate the denominators in the 2 fractions so you get 12 + 20x = 30x^2 or 30x^2 - 20x -12 = 0 divide by 2 15x^2 - 10x - 6 = 0 now you have a quadratic to solve.. hope this helps
so I would solve 15x^2 - 10x - 6 = 0?
yes.... probably general quadratic formula is best
what if I need it as a fraction?
well I think you'll find its an irrational solution....
cause my thing says that im supposed to end up with a fraction :/
well if you use the general quadratic formula you will get a fraction.... \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] but its irrational
is there a way to do it with out the general quadric formula? because I don't think I have even heard of that in class yet
well look at the discriminant... \[b^2 - 4ac \] its 460 which isn't a perfect square. so the the GQF seems best... an alternative is complete the square...
hmm... I can't seem to factor it either without quadratic formula... try this? http://www.wolframalpha.com/input/?i=15x%5E2+-+10x+-+6+%3D+0
its a review of 8th grade math...I don't think it can possably be so complicated
ok... well perhaps you should ask you teacher, show the teacher what you have done... and if its 8th grade the problem makes more sense as \[\frac{4}{5} x + \frac{4}{3} = 2x\] by subtracting 4/5 x you get \[\frac{4}{3} = \frac{6}{5} x \] just solve for x
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