Triangle DOG is transformed using a reflection. Which could be coordinates of D'O'G' after the reflection? A. D=(0,0), O=(-1,-2), G=(1,4) B. D=(0,0), O=(-1,-2), G=(1,-4) C. D=(0,0), O=(-2, 1), G=(-1, -4) D. D=(0,0), O=(-1,2), G=(1,4)
please help me!
@mathman806
@mathcalculus
reflection on the x-axis or , y-axis ??
y- axis :)
please help!
find out where wud O go
rule for reflection in y-axis :- (x, y) ---> (-x, y)
wat are the coordinates of point O before reflection ?
Before reflection, (1,2) After: (-1,2)?
Awesome :) Now look at ur options
is it the last one?
brilliant !!
Thank you so much! can you help me with another one?
yea sure :)
|dw:1381782049565:dw|
Whats this?^
this is how the triangle looks after reflection :)
What additional information would you need to prove that ΔABC ≅ ΔDEF by SAS? A. segment AC ≅ segment EF B. segment BC ≅ segment FE C. segment AC ≅ segment FE D. segment BC ≅ segment EF
this is the traingle after reflection
oh okay thanks :)
look at ur options, see that none of them have angles. all of them have SEGMENTS
yeah I see that
good :) now, look at the triangles. wat info we're given ?
That AB and DE are congruent?
Yes ! and ?
also, \(\angle B \cong \angle E\)
they both have one green arc on them, indicating they're congruent
yes I was going to type that! ahah
oops! sorry about that.. still good, you have another question :- which postulate u can use to prove these triangles are congruent ?
use the fact that, ur options have all Sides
I dont know what postulate means:(
SAS SSS ASA
those are the congruence postulates
or theorems or w.e
since we're given Side and Angle are congruent we just need another Side to use SAS
that side wud be :- \(\large BC \cong EF\) you tell me why
thats the answer btw..
oh okay thank you so much, that would be the side because that is the side that is not identified as anything?
thats partially correct, but ok.. i see u wil get hang of these as these after doing few more problems :) dont rush yet, you're doing great !
Line 1 - segment AB equals 2, segment FD equals 2, segment AB is congruent to segment FD Line 2 - ∠A ≅ ∠F Line 3 - Length of segment AC. A (1, 2) C (3, 3) segment AC = 2.23 Line 4 - Length of segment EF. E (3, 2) F (5, 3) Line 5- segment AC is congruent to segment FE Line 6- triangle ABC is congruent to triangle EFDby SAS
picture for line 3
picture for line 4
Please help @ganeshie8 I really need to pass
is that the whole question ? or is there a triangle/lines pic that goes wid this question ?
oh yeah here sorry
I think it is line 5 but Idk
Line 6 has a serious problem
Line 6- triangle ABC is congruent to triangle EFDby SAS ^ ^
first triangle started wid A second triangle started wid E
*look at the pic, A and E are not equal !
oh so line 6 is the answer?
yes
i need to go, please close this... and ask a new question.... good luck !!
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