Question

Write an equation in standard form for a line with an x-intercept of 3 and y-intercept of 6.
A. 2y+x-6=0
B. y+2x-6=0
C. y+2x-3=0
D. 2y+x+3=0

Answer 1

so you're really given 2 points

notice the value of "x" at the y-intercept, is 0 thus ( 0 , 6 )
notice the value of "y" at the x-intercept, is 0 thus ( 3, 0 )

so, find the slope of the line using those 2 points, \(\bf slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\)

once you find the slope, use either point, and plug those values, the found slope and the coordinates of the point, and solve for "y" in the point-slope form of \(\bf y-y_1=m(x-x_1)\)

Answer 2

Thank you for explaining that thoroughly.