3A(g)+2B(g)⇌C(g)
Kc = 44.0 at a temperature of 219∘C .
Calculate the value of Kp.

so far I have

D n = -4

T = to 492 K

Kc = 44

Kp = kc ( RT)^dN

Kp = 44(.08206 * 492)^ -4

Kp = .000017 or 1.7 * 10 ^-5

What am I doing wrong here?
But it's not right

Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures.

Question

3A(g)+2B(g)⇌C(g)
Kc = 44.0 at a temperature of 219∘C .
Calculate the value of Kp.

so far I have

D n = -4

T = to 492 K

Kc = 44

Kp = kc ( RT)^dN

Kp = 44(.08206 * 492)^ -4

Kp = .000017 or 1.7 * 10 ^-5

What am I doing wrong here? 
 But it's not right

Not quite. Check through your calculations; you may have made a rounding error or used the wrong number of significant figures.

anonymous · Answer

@Preetha  Hello, can you help me figure out what I did wrong here? I'm pretty sure it's something really simple.