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OpenStudy (anonymous):
x is a normally distributed random variable with a mean of 1, and p(-4
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OpenStudy (zarkon):
p(-4<x<-2)=p(4<x<6)
OpenStudy (anonymous):
is that the answer?
OpenStudy (anonymous):
if so , how you figure?
OpenStudy (zarkon):
it is not the final answer...it will lead you to the answer though
OpenStudy (anonymous):
how if It doesnt show me the standard deviation
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OpenStudy (zarkon):
you don't need the standard deviation to answer this problem
OpenStudy (anonymous):
all I know is that the intervals |-4,-2| |4,6| are symmetric, but I cant figure the answer.
OpenStudy (zarkon):
do you agree that p(-4<x<-2)=p(4<x<6)?
OpenStudy (anonymous):
no because one is negative and the other is positive. right?
OpenStudy (zarkon):
well they are the same...using this fact we can get ...
p(-4<x<-2)+p(4<x<6)=.2
p(-4<x<-2)+p(-4<x<-2)=.2
2*p(-4<x<-2)=.2
p(-4<x<-2)=.1
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OpenStudy (anonymous):
I have to find that formula. That makes so much sense. thanks.
OpenStudy (anonymous):
is this the final answer?
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