calculate the grams for
a)11.3dm^3 of so2 at stp
b)0.16 moles of magnesium sulphate
c)165cm^3 of a 0.36M MgSO4 solution

Question

calculate the grams for 
a)11.3dm^3 of so2 at stp
b)0.16 moles of magnesium sulphate
c)165cm^3 of a 0.36M MgSO4 solution

anonymous · Answer

yea this was my question

ankit042 · Answer

1 mole of gas at STP has 22.7 liters

mass of 1 mole of chemical compound is mass of individual elements*their valency

ankit042 · Answer

22.4 liters*

ankit042 · Answer

1dm^3 = 1 liter
so 11.3 liter= 11.3/22.4 moles
Now calculate the mass of so2 and multiply with moles

ankit042 · Answer

does this makes sense to you @csmith0355

anonymous · Answer

yes it does  im trying to calculate it now

anonymous · Answer

i got 32g

ankit042 · Answer

Yeah it will be around 32...good work

anonymous · Answer

thanks ;lol.. for the second one i should find the grams od mg sulphate right

ankit042 · Answer

you can calculate the mass of 1 mole of compound just multiply with 0.16

anonymous · Answer

0.16 divided by 120?

ankit042 · Answer

why divide?

anonymous · Answer

im not sure why but i didnt see any other way

ankit042 · Answer

if 1 mole weights X grams
how much will y moles weight?

ankit042 · Answer

let me put this way 1 candy bar cost X dollars
how much will Y candies cost?

anonymous · Answer

do u mean 6.0 x10^23?

ankit042 · Answer

idk from where you got 6.0 x10^23 answer will be 0.16*120

anonymous · Answer

avagados number thats where i got it from

ankit042 · Answer

yeah I know that but how is avagados number relevant for this question

anonymous · Answer

i thought it was my bad

ankit042 · Answer

Yeah whatever let me just give you 3rd answer M =m/v where M is molarity . m is number of moles of solute and V is volume of solvent . find the moles of MgSO4 and then it is same as part b

anonymous · Answer

thanks alot! got it

ankit042 · Answer

np :)

anonymous · Answer

r u good at stoichemistry ?

anonymous · Answer

or can recommend someone on this

ankit042 · Answer

I was good at stoichemistry. Don't have to use it now days so don't remember but you can contact @abb0t or @nincompoop

anonymous · Answer

@abb0t  would you be able to help me understand stoi chemistry i am having problems understanding it and i have an exam 2morrow

abb0t · Answer

I don't understand, what's the question here?

anonymous · Answer

i havent posted it as yet i was just trying to find someone to help me i will post it now

abb0t · Answer

ok.