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simplify the radical, radical(4t^2+4t^4+1)
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Factor :)
\[ 4t^2+4t^4+1=4t^4+2t^2+2t^2+1=2t^2(2t^2+1)+1(2t^2+1)=(2t^2+1)^2 \]
^ he is right. Another solution would be to represent t^2 as a It will simplify the equation to 4a^2 + 4a + 1 the factor would be (2a+1)^2 so substitute the real value of a which is t^2 it will be (2t2+1)2
you guys are genius
What was your final answer?
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well the question was to find the tangential unit vector, r(t)=<t^2,2/3 t^3, t>
Oh I see.
Using it for a line integral, or just something else?
forgot about factoring lol. uhm, curvature. its a quiz problem says to find t(t) and n(t)
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