Question

Find vertical asymtotes for (x^3-10x^2+16x)/(x^2-8x) I know that x cannot equal 0 or 8, where do I go from here?

Answer 1

ok I gotcha

Answer 2

ya still there?

Answer 3

yes i am

Answer 4

one sec while I figure it out

Answer 5

is there any way you can plug that in using the equation editor for me?

Answer 6

\[(x^3-10x^2+16x)/(x^2-8x)\]

Answer 7

Tell me the steps on how to attain the answer, I don't need to know the answer I need to know the how rather than end, thanks!

Answer 8

This problem is sort of a trick question.\[\frac{x^3-10 x^2+16 x}{x^2-8 x}=x-2 \]A plot is attached.

Answer 9

could I see this done arithmetically?

Answer 10

there are no vertical asymptotes

Answer 11

\[\frac{x^3-10 x^2+16 x}{x^2-8 x}=\frac{((x-8) (x-2) x)}{((x-8) x)}=x-2 \]

Answer 12

am I right rob?

Answer 13

@llkramer
Yes.