Question

You have three $1 bills, four $5 bills, and two $10 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill at random. Find P($5 then $10).

Answer 1

Answer: you got more money than me xD

Answer 2

For the first pick, how many bills are there in total?
For the first pick, how many $5 are there?

For the second pick, how many bills are there in total?
For the second pick, how many $10 are there?

Answer 3

Lol, Mttblink. and hmmm
1-9
2-4
3-9
4-2
i think?

Answer 4

1 and 2 are correct. there are a total of 9 bills and there are 4 $5 bills before you pick the first time.
For 3 and 4, once you already picked a $5 bill, and you are ready to do the second pick, there are now only 8 bills left, not 9. Of those, 2 are $10 bills.
OK?

Answer 5

okay. i need it in fraction form though

Answer 6

The probability of the the 2 picks are:
P($5) = 4/9
P($10) = 2/8 = 1/4

So P($5 then $10) = P($5) * P($10)

Answer 7

I dont uderstand :c

Answer 8

Multiply the two probabilities.

P($5 then $10) = P($5) * P($10) = 4/9 * 1/4 = 1/9

Answer 9

Is the answer 2 over 27?