find the values of the indicated trigonometric functions. Find cscθ, given cosθ=0.1063
@robtobey
do you have answers I can choose from?
no sorry
mmm ok I think I know but I don't wanna point you in the wrong direction if im wrong
@Grazes
Do you know your trig identities?
1/0.1063=9.41
not to well no
Well, you know that csc(θ) = 1/sin(θ), right?
yes
Have you learned that sin2 θ + cos2 θ = 1?
no
sin^2(θ) + cos^2(θ) = 1 is the function of the unit circle. I don't believe there is a simply way to convert cos to csc, but do you know sin^2(θ) = 1 − cos^2(θ) OR cos^2(θ) = 1 − sin^2(θ)
\(\bf csc(\theta) = \cfrac{1}{sin(\theta)}\qquad if \qquad cos(\theta)=sin(90^o-\theta)\qquad thus\\ \quad \\ csc(\theta) = \cfrac{1}{sin(90^o-\theta)}\)
assuming is 0.1063 degrees, as opposed to radians
\(\bf csc(\theta) = \cfrac{1}{sin(\theta)}\qquad if \qquad cos(\theta)=sin\left(\frac{\pi}{2}-\theta\right)\qquad thus\\ \quad \\ csc(\theta) = \cfrac{1}{sin\left(\frac{\pi}{2}-\theta\right)}\) if it's 0.1063 radians
1^2+0.1063^2 1=+0.1129969=1.01129969=1.0056
1/sin 1.00560=56.97
hhh... smokes... I misread.. again hehe... ahemm is just a value..... dohh
lemme redo that
ok
\(\bf cos(\theta) = 0.1063\qquad \textit{we know that}\quad cos(\theta) = sin\left(\frac{\pi}{2}-\theta\right)\quad thus\\ \quad \\ cos(\theta) = 0.1063\implies sin\left(\frac{\pi}{2}-\theta\right) = 0.1063\\ \quad \\ \quad \\ csc(\theta) = \cfrac{1}{sin(\theta)}\qquad thus \qquad \cfrac{1}{sin\left(\frac{\pi}{2}-\theta\right)} = \cfrac{1}{0.1063}\)
more or less all we did was, grab the equation \(\bf sin\left(\frac{\pi}{2}-\theta\right) = 0.1063\) and raise both sides at -1
which will give the inverse of sine, which is the cosecant, for the same angle
ok sol e me see what i get real quick
0.1061
\(\bf \cfrac{1}{0.1063} \quad ? \)
oops 9.41
yeap
lol i just s aw that
so was doingi t correctly in the first p lace
yes
ok great i just wa s unsure
sorry for the lagg in my computer
tis ok
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