Question

Hello there, I need help with this algebraic expressions problem. A= 3/2 B=5/2 c= 1/2
So 7-a+b-1-c. I keep getting 8 or some other wrong answer.

Answer 1

\[7 - \frac{3}{2} + \frac{5}{2} - 1 - \frac{1}{2}\] since almost all the terms have a 2 in the denominator, it will be easiest to make the 7 and 1 have a 2 in the denominator as well, you do it like this \[\frac{14}{2} - \frac{3}{2} + \frac{5}{2} - \frac{2}{2} - \frac{1}{2}\] simplify \[\frac{14 - 3 + 5 - 2 - 1}{2} = \frac{13}{2}\]

Answer 2

The answer is 7 1/2

Answer 3

You're sure?? because what i got is correct and \[\frac{13}{2} = 6 \frac{1}{2}\]

Answer 4

That is the answer in the book

Answer 5

I'm.sorry. c is - 1/2

Answer 6

Then either there is a typo or you copied the equation wrong because 7 - a + b - 1 - c = 13/2 with the values you have provided

Answer 7

Yeah c is a negative 1/2 not positive the other variables are positive

Answer 8

ok so \[\frac{14}{2} - \frac{3}{2} + \frac{5}{2} - \frac{2}{2} + \frac{1}{2} = \frac{14 - 3 + 5 -2 + 1}{2} = \frac{15}{2} = 7\frac{1}{2}\] thats better :)

Answer 9

Wait for some reason I cannot see the rest of your evaluation after -2

Answer 10

7 - 3/2 + 5/2 - 1 - 1/2 (multiply the entire equation by 2)
14 - 3 + 5 - 3 - 1
19 - 7 = 12

Answer 11

wait...I made a mistake

Answer 12

7 - 3/2 + 5/2 - 1 - 1/2 (multiply by 2)
14 - 3 + 5 - 2 - 1
19 - 6 = 13

Answer 13

Thank you Tyler but im still confused .why are you multiplying the whole thing by 2 ?

Answer 14

You dont multiply the whole thing by 2

Answer 15

you want all the terms to have a common denominator, since there were already 3 terms with a 2 in the denominator, it would be easiest to make the 7 have a 2 in the denominator and the 1 to have a 2 in the denominator.

Answer 16

I did 7/1 -3/2 + 5/2 -1/1/ * -1/2

Answer 17

right initially you have \[\frac{7}{1} - \frac{3}{2} + \frac{5}{2} - \frac{1}{1} + \frac{1}{2}\]

Answer 18

Oh oh ohjhhhhhhhhhh. Now I get it I'm doing to much of theese math problems so I just experienced a brain fart haha

Answer 19

Thank you

Answer 20

in order to add fractions, every fraction must have the same denominator

Answer 21

You good now? lol

Answer 22

Lol yeah I just need a break or something oh gosh

Answer 23

Thanks for pointing that out and thank you Texas girl