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g(f(x)) and f(f(x)) when f(x)=3x/x-1 g(x)=x/x-3
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@Directrix
@Mertsj
\[g(f(x))=\frac{\frac{3x}{x-1}}{\frac{3x}{x-1}-3}=\frac{3x}{3x-3(x-1)}=\frac{3x}{3}=x\]
\[f(g(x))=\frac{3\times \frac{x}{x-3}}{\frac{x}{x-3}-1}=\frac{3x}{x-(x-3)}=\frac{3x}{3}=x\]
So we see that the functions f and g are inverse functions because by definition if f(g(x))=x and g(f(x))=x, then f and g are inverse functions.
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right :) so how about f(f(x))
Can you try that now?
3*3x/x-1/3x/x-1
@Mertsj
??
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You forgot the -1 in the denominator
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