Find the discriminant for each equation. Describe the roots. Give D, then the number of rational, irrational or complex roots. ( ex: 36, 2 rational) 25 + 4x2=-20x
ive done this problem and i got the answer inncorrect and im not sure why just trying to compare answers with someone for my online class
once you put the equation into polynomial form, the discrimanent is the part under the square root in the quadratic formula
i'll work it out with you
its (4)^2-4(25)(-20) right?
4x^2 + 20x + 25 = 0 so a=4 b=20 c=25 then the discrimnant is b^2 - 4ac so 20^2 - 4 (4) 25 = 0 now here are the root possibilities depending on what the value of the discrimiant is: (by the way, ours is 0) if its > 0, the roots are real numbers and unequal if its = 0, the roots are real numbers and equal if its < 0, the roots are complex numbers and unequal make sense?
oo im sorry i wrote 20 and 4 in different places :/
could you help me on Find the discriminant for each equation. Describe the roots. Give D, then the number of rational, irrational or complex roots. ( ex: 36, 2 rational) 2x -5 = -x2
is it (5)^2-4(2)(-1)??
2x - 5 = -x^2 first move all the terms to one side x^2 + 2x - 5 = 0 then identify the A, B, C coeffients whcih go into the quadratic equation. now, these are the posistions of the coefficients A, B, C Ax^2 + Bx + C = 0 <- this is the standard form so we will extract A, B, and C from your equation using the placements given to us from the standard form, so A = 1 B = 2 C = -5 make sense so far?
yuppp got it
wait soo it would b (2)^2-4(1)(-5)
yep, you got it!
thank ya
you are welcome
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