If an electric dipole is placed along the X axis and we measure the potential at a point in the negative X axis then why does the sum of the potential not becomes zero.

Question

praxer · Answer

|dw:1381951889730:dw|

abb0t · Answer

I'm not sure. But Isn't this refering to superposition principle? You have more of a  pull on A.

praxer · Answer

attachment

praxer · Answer

In the attachment there is a example and in the solution it is given that there is no possibility of potentials due to two charges to adding upto zero for x<0

abb0t · Answer

I think for this you should be using $\sf \color{}{F = 2aqr_0}$ ? Right? In terms of el. dipole.

praxer · Answer

hmmm, but when it comes for potential it is pk/r^2 in an axial dipole

abb0t · Answer

Isn't that torque??

abb0t · Answer

Sorry I forgot all my phsycs I took E&M like 4 years ago. And I have no books to help me. lol

praxer · Answer

But the question said about potential, so i think we should not bring about electric field. Because in the solution it was given that on the negative axis there is no possibility of the potential to become Zero.

abb0t · Answer

Maybe @zepdrix can help.

anonymous · Answer

I don't have much experience with this topic in physics... I just started physics recently (on vectors displacement and the like...) Sorry, @praxer! Maybe you could help me out?

praxer · Answer

@e.mccormick  can u hlp me undrstnd this..

abb0t · Answer

I'm sure @Luigi0210 can help.

praxer · Answer

@abb0t no one did help :(