Question

Calculus help pleasee

Find any critical numbers of the function.
f(theta) = 2 sec theta + tan theta , 0< theta < 2 pi

Answer 1

Take the derivative of your function and set it equal to zero.

Answer 2

well, I can do that.

Answer 3

I'm asking for help on solving for a derivative.

Answer 4

\[f(\theta) = 2\sec\theta + \tan\theta\]\[f'(\theta) = 2\sec\theta\tan\theta + \sec^2\theta \]

Answer 5

crit points are where the slope of the graph = 0?

Answer 6

@SACAPUNTAS Yay! I got the right derivative. then you have to set that equal to 0 and solve for theta right? sorry I had to mention that earlier :(

Answer 7

Yes like @dan815 said, it's where the slope (i.e. the derivative) = 0

Answer 8

then do you think this step is right?
after you found the derivative, I did
sec theta(2tantheta + sec theta) = 0

Answer 9

and I divided sec theta on both sides so it became
0 = 2 tan theta + sec theta ?

Answer 10

and I was kinda stuck there.. :(

Answer 11

\[\large f'(\theta) = 2\sec(\theta)\tan(\theta) + \sec^2(\theta)=0\]\[\large f'(\theta) = \sec(\theta)(2\tan(\theta) +\sec(\theta))=0\]