derivative qn
figured out this one ?
yup! thanks!(: i just figured out how to work backwards(: like in this qn, f(a) =2, f(a+h)=(16+h)^1/4. (^1/4) is the clue thus, if f(x)=x^1/4 =2 then a=16. (:
so f'(x) = d/dx x^1/4 = (x^(3/4))/4, f'(16)= 1/32, isit correct?
Excellent !!!! thats correct !!
thank you! :D
thank yourself :))
nah, i analyzed the previous qn i asked you, the same type but just different variables, finally got what u mean by working backwards, thanks!(:
another f(x) that wud work here is :- \(\sqrt[4]{x+16}\), and a = 0
i got this first, cuz was looking for some function at a = 0 but x^1/4 looks more elegant... :)
i see.. ya, no wonder the previous qn you used a=0 also haha, anyways either way it must end up the same (:
yup ! there can be many f(x) and a's
for all of them, f'(a) will endup 1/32
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