Identify whether the series is a convergent or divergent geometric series and find the sum, if possible.
@dan815
@Jonathan1997
This is a convergent geometric series. The sum is 48. This is a divergent geometric series. The sum is 48. This is a convergent geometric series. The sum cannot be found. This is a divergent geometric series. The sum cannot be found. Almost Forgot this
its convergent because its a geometric series, r = 5/6
ok so now i just need to find the sum if there is one.
so number 3 right
if the sum is convergent , and can be found
the sum is convergent and can be found. the sum is 48
wait i fail
I know the answer
summation of 8(5/6)^(I-1) from i=1 to infinity
http://www.wolframalpha.com/input/?i=summation+of+8%285%2F6%29%5E%28I-1%29+from+i%3D1+to+infinity
See https://en.wikipedia.org/wiki/Geometric_series#Formula which shows the formula and a derivation if you are interested
notice in wolfram.. you have to read the fine print. wolf is assuming i stands for sqr(-1). if you used k for the index, you would get the correct answer.
@phi so my answer was wrong?
what was your answer ?
This is a divergent geometric series. The sum cannot be found.
the sum is convergent and can be found. the sum is 48
its a geometric series , |r|<1
http://www.wolframalpha.com/input/?i=summation+of+8%285%2F6%29%5E%28I-1%29+from+i%3D1+to+infinity according to this it is divergent and the sum cannot be found
it is convergent, so you are incorrect. if you get a calculator and find (5/6)^2 and (5/6)^3, and so on... you will see that when n is very big (5/6)^n is getting closer and closer to 0
okay but can the sum be found?
Help - re-read my post up above more carefully
oh sorry, nevermind. help, you inputted wrong
help, this is correct input http://www.wolframalpha.com/input/?i=summation+of+8%285%2F6%29^%28i-1%29+from+i%3D1+to+infinity
Thank you very much
help you used I and i, can't change the letter
ok
phi, do you have any experience with maple syntax
@perl re: maple, not enough to be helpful
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