Question

show that:

Answer 1

wat?

Answer 2

\[\int\limits_{0}^{\frac{ \pi }{ 2 }}\sin^2x dx\]

Answer 3

i evaluated in the previous question the same thing, except it wasn't sin^2 (x) but x*sin(x). Would these be related?

Answer 4

oh sorry. the first one has to equal to pi/4

Answer 5

Recall that \[ cos(2x) = 1-2sin^2(x) \] implies \[sin^2(x) = \frac{1-cos(2x)}{2} \]

Replace, and that should be easier to integrate.

Answer 6

thank you :)