Question

Solve the system by elimination.

-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5

Answer 1

Can you help @Luigi0210

Answer 2

Sorry, I never learned how to solve this by elimination..

Answer 3

know anyone who could help?

Answer 4

@phi maybe?

Answer 5

if we just write down the coefficients:
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5

-2 2 3 0
-2 -1 1 -3
2 3 3 5

The idea is make the first column all zeros below the first -2
replace the second row with first row - second row

can you do that ?

Answer 6

I'll do the first step: zero out the -2 just below the first -2

to do that we do 2nd row - 1st row:
-2 -1 1 -3 <-- 2nd row
2 -2 -3 0 <--- minus 1st row. Now add
0 -3 -2 -3 <-- new 2nd row


the problem is now
-2 2 3 0
0 -3 -2 -3
2 3 3 5

now we want to zero out the bottom 2. replace the last row with last row + 1st row
what do you get ?