find the value of cot(11pi/6)
the exact value or just value
my paper only says value so thats what im going off of
remember that 11pi/6 is in 4th quadrant, so only cos and sec ratio will be positive... cot(11pi/6)=-cot (2pi-11pi/6)---->as cot x=-cot(-x)=-cot (2pi-x) =-cot(pi/6)=- sqrt(3) now cos(11pi/6)=cos (2pi-11pi/6)---->as cos x=cos(-x)=cos (2pi-x) =cos(pi/6)=sqrt(3)/2 csc(11pi/6)=-csc (2pi-11pi/6)---->as csc x=-csc(-x)=-csc (2pi-x) =-csc(pi/6)=- 2
i know the answer is the sqrt of 3 i just dont get were the -cos and the 2 comes from
Well is this for Geometry.
advance function and modeling
Oh then sorry thats alittle more advanced than i have gone with math.
ok well thanks anyways
Yah Im only in Geometry and the highest math ive worked with is precal and that was for an engineering class.
Join our real-time social learning platform and learn together with your friends!