Question

What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)?

Answer 1

\[slope = \frac{ y _{2}-y _{1} }{ x _{2}-x _{1} }\] when given coordinates (x1,y1) and (x2,y2)
and point-slope form is y - y1 = m(x-x1)
so you find the slope and plug in to the format

Answer 2

so y-0=-3(x-4)

Answer 3

yes :)

Answer 4

what about this question What is the equation in standard form of the line which passes through (4, −2) and has a slope of −3?

Answer 5

well you know how to put it into y - y1 = m(x-x1) right?
then you try to get it into ax+by+c = 0 form
basically to get from y - y1 = m(x-x1) to standard form, you simplify and move everything to one side :)

Answer 6

so my first step would be y+2=-3x-4

Answer 7

be careful, there is distributive property so it is y+2=-(3x-4)
which equals y+2=-3x+12
parenthesis matter :P

Answer 8

so no i distribute the -?

Answer 9

oh wait, the slope is -3 so
the point-slope equation should be y+2=-3(x-4)
which equals y+2=-3x+12
sorry for confusing you there

Answer 10

so no i subtract 12?

Answer 11

y+2=-3(x-4)
y+2=-3(x)+(-3)(-4)
-3 * -4 = positive 12

Answer 12

i ment now i subtract 12 to get it to the other side right?

Answer 13

oh yeah, yes :)

Answer 14

can i subtract 2 insted?

Answer 15

you can if you want, but by doing that you'll have a bunch of negative values on one side, while if you subtract 12 you it becomes easier on the eyes to look at and comprehend...
but it is a preference thing so yes you can :)

Answer 16

i got 3x+y=10

Answer 17

yes, that is correct :D