Ask your own question, for FREE!
Mathematics 6 Online
OpenStudy (anonymous):

Write a function for each graph described as a transformation of y=x^2. A. y=x^2 undergoes a shift left of 2 units, then a reflection through the x-axis. B. y=x^2 undergoes a horizontal stretch by a factor of 1/3, then a shift up of 4 units.

OpenStudy (anonymous):

\[A. \space y = -(x+2)^2\]

OpenStudy (anonymous):

\[B. \space y = \frac{1}{3}x^2 + 4\]

OpenStudy (anonymous):

youre amazing! thanks! :)

OpenStudy (anonymous):

do you know how to find the intercepts, vertex and axis of symmetry of this graph? @Tyler1992

OpenStudy (anonymous):

the intercepts are where the graph crosses the x axis. I think you can handle that one

OpenStudy (anonymous):

And the vertex is the lowest point of the graph.

OpenStudy (anonymous):

for the intercepts i got (-3,0) and (1,0)

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

so the vertex would be -4?

OpenStudy (anonymous):

Ok i should rephrase the vertex statement lol

OpenStudy (anonymous):

depending on if the parabola opens up or down the vertex is the lowest point if it opens up and highest point if it opens down

OpenStudy (anonymous):

in this case it opens up so the lowest point would be (-1,-4)

OpenStudy (anonymous):

got it, thanks :)

OpenStudy (anonymous):

axis of symmetry should be x = -1 sorry

OpenStudy (anonymous):

its the x coordinate of the vertex

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!