Write a function for each graph described as a transformation of y=x^2. A. y=x^2 undergoes a shift left of 2 units, then a reflection through the x-axis. B. y=x^2 undergoes a horizontal stretch by a factor of 1/3, then a shift up of 4 units.
\[A. \space y = -(x+2)^2\]
\[B. \space y = \frac{1}{3}x^2 + 4\]
youre amazing! thanks! :)
do you know how to find the intercepts, vertex and axis of symmetry of this graph? @Tyler1992
the intercepts are where the graph crosses the x axis. I think you can handle that one
And the vertex is the lowest point of the graph.
for the intercepts i got (-3,0) and (1,0)
correct
so the vertex would be -4?
Ok i should rephrase the vertex statement lol
depending on if the parabola opens up or down the vertex is the lowest point if it opens up and highest point if it opens down
in this case it opens up so the lowest point would be (-1,-4)
got it, thanks :)
axis of symmetry should be x = -1 sorry
its the x coordinate of the vertex
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