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Calculus1 6 Online
OpenStudy (anonymous):

help with calculus ! f(x)= x/(lx^2-9l) What is the domain? i also have to write an equation for each vertical & horizontal asymptote

OpenStudy (agent0smith):

To find the domain... remember that the denominator can not be equal to zero, so find where it's equal to zero.

OpenStudy (anonymous):

Oh okay . so just make the denominator = to 0? and figure it out from there?

OpenStudy (anonymous):

Yep

OpenStudy (agent0smith):

There's only two x values that give a denominator of zero.

OpenStudy (anonymous):

okay thanks! do you know how to write an equation for each horizontal & vertical asymptote?

OpenStudy (agent0smith):

Vertical asymptotes will be the same as the x values that make the denominator zero. Horizontal is a bit more complex... you want to look at the highest powers on the numerator and denominator.

OpenStudy (anonymous):

how would i write them as an equation tho?

OpenStudy (agent0smith):

x = ... y = ...

OpenStudy (anonymous):

so when you say power you mean x^2 . so the highest power will be 2?

OpenStudy (agent0smith):

Yep. Highest power on the top is x. On the denominator is |x^2| Do you know what happens to y= x/|x^2| as x approaches infinity? what will y approach?

OpenStudy (anonymous):

No . i'm not sure. my teacher tried explaining this to me but i could not grasp what he was telling me

OpenStudy (anonymous):

does y get closer to 0?

OpenStudy (agent0smith):

Yes... x/x^2 simplifies to 1/x... which when x is huge, 1/(huge number) is ~zero as x approaches neg infinity, same thing, y approaches zero

OpenStudy (agent0smith):

as x gets larger, 1/x gets closer to zero

OpenStudy (anonymous):

oh okay. ty

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