help with calculus ! f(x)= x/(lx^2-9l) What is the domain? i also have to write an equation for each vertical & horizontal asymptote
To find the domain... remember that the denominator can not be equal to zero, so find where it's equal to zero.
Oh okay . so just make the denominator = to 0? and figure it out from there?
Yep
There's only two x values that give a denominator of zero.
okay thanks! do you know how to write an equation for each horizontal & vertical asymptote?
Vertical asymptotes will be the same as the x values that make the denominator zero. Horizontal is a bit more complex... you want to look at the highest powers on the numerator and denominator.
how would i write them as an equation tho?
x = ... y = ...
so when you say power you mean x^2 . so the highest power will be 2?
Yep. Highest power on the top is x. On the denominator is |x^2| Do you know what happens to y= x/|x^2| as x approaches infinity? what will y approach?
No . i'm not sure. my teacher tried explaining this to me but i could not grasp what he was telling me
does y get closer to 0?
Yes... x/x^2 simplifies to 1/x... which when x is huge, 1/(huge number) is ~zero as x approaches neg infinity, same thing, y approaches zero
as x gets larger, 1/x gets closer to zero
oh okay. ty
Always helps to use a graph to confirm it https://www.google.com/search?q=1%2F10000000000&oq=1%2F10000000000&aqs=chrome..69i57j69i58j0.2651j0j7&sourceid=chrome&espv=210&es_sm=93&ie=UTF-8#es_sm=93&espv=210&q=x%2FABS(x%5E2-9)&safe=off
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