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Compute the derivative f'(a) algebraically, using the definition, for the given value of a. f(x)= x-2xˆ3, a=1
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\[f'(a)=\lim_{\Delta \rightarrow 0}\frac{f(a+\Delta)-f(a)}{\Delta}\] So do you know know to find: \[f(a+\Delta)?\]
i know that my a would be 1 but how do i find \[\Delta\]
that is going to zero....
\[f(a+\Delta)=(a+\Delta)-2(a+\Delta)^3\] Plug this into our definition and simplify our fraction as much as possible.
Like you would multiply that (a+Delta)^3 thing And cancel some stuff on top. If you want to go ahead and replace a with 1, that is cool.
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Okay! Thanks a lot :)
Have you simplified the fraction? After simplifying the fraction you should be able to plug in 0 for delta.
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