A 69-kg base runner begins his slide into second base when he is moving at a speed of 3.6 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base.

(a.) How much mechanical energy is lost due to friction acting on the runner? (In Joules)

(b) How far does he slide? (in Meters)

Question

A 69-kg base runner begins his slide into second base when he is moving at a speed of 3.6 m/s. The coefficient of friction between his clothes and Earth is 0.70. He slides so that his speed is zero just as he reaches the base. 

(a.)  How much mechanical energy is lost due to friction acting on the runner? (In Joules)

(b) How far does he slide? (in Meters)

anonymous · Answer

we will set up the equation in two events.
event 1 is the instant he starts to slide
event 2 is the moment he stops sliding

KE_1 - friction = KE_2

does that help?

anonymous · Answer

It's definitely a start. I'm going to try to work the problem out real quick, and come back to you in 5 minutes, if I get it wrong.

anonymous · Answer

sounds good, just remember that KE = (1/2)*m*v^2

anonymous · Answer

Whoo hoo! I got it right. Thanks DemolisionWolf, you're the best!

anonymous · Answer

hey, glad it made sense! 
the trick on this one was know that KE_final has a velocity = to zero

so you have part A and B then?

anonymous · Answer

Yep ^_^

anonymous · Answer

great, happy i could help
(medal please?)