Question

Hey, I have a HUGE test tomorrow. The only thing I am is having trouble with is Linear Equations. Can you guys give me some hints on what to do. (My math book is NO help)

Answer 1

Are these linear equations in one variable?

Answer 2

yes @terenzreignz

Answer 3

What part do you find hard about them?
And it doesn't surprise me. Math books are usually bad at explaining simple stuff like this in basic terms.

Answer 4

Well, the rule of thumb is bring all terms with a variable to the left side of the equation and all the terms without variables (constants) to the right.

Answer 5

the part where you have to find the variable y. @SACAPUNTAS

Answer 6

So is the problem the algebra involved in getting y by itself?

Answer 7

Do what terenzreignz said. Remember you always have to do the same thing to both sides of the =. (e.g., if you add 2 to one side, you have to add 2 to the other side also)

Answer 8

What I am asking is how do i find of what y is. @SACAPUNTAS

Answer 9

\[y = 2x - 3\]So just put in the given value of x and do the math.
Like when x = 0, y = 2(0) - 3 so y = -3.

Answer 10

Sorry, I still don't understand how you get the value of y @SACAPUNTAS

Answer 11

Ok, you know that \(y = 2x - 3\). And you know the value of x.
So you just put in the value you know for x anywhere you see an x.

Answer 12

So if x is 0 I do 2(0) - 3. Or if x is 5 I do 2(5) - 3. Or if x is 999 I do 2(999) - 3.

Answer 13

Basically, you take the value for x listed in the table, put that value in anywhere you see an x, and you'll end up with an expression that looks like \(y =\) some number.

Answer 14

Oh, Thanks! I finally got it! Thank you so much!! Your the best @SACAPUNTAS

Answer 15

Glad to help. Good luck in your mathematic endeavours. :D