Question

find the equation of the line passing through the points P(1,1)and Q (4,-1) trying to figure out how to put answer in standard form

Answer 1

The slope is -2/3
first put it into point slope form with the point (1,1)

Answer 2

y-y1=m(x-x1)

Answer 3

I got the -2/3

Answer 4

but it says to put answer in standard form

Answer 5

where is the 5 coming from

Answer 6

so y-1 = -2/3(x-1) distribute and isolate y

Answer 7

k Ive got that

Answer 8

it gives me these answers to choose from
a) 2x-3y=-5
b)2x+3y=5
c)3x+2y=5
d)3x-2y=-5

Answer 9

y=-2/3 x+5/3
since the entire right side is divided by 3, multiply the enire equation by 3 to get closer to standard form.

Answer 10

If standard form is Ax+By=C, then the normal form is usually y=-A/B x + C/B

Answer 11

use that and see what you get

Answer 12

still trying to figure out where the 5 is coming from?

Answer 13

nevermind I will figure it out

Answer 14

Find the slope using the slope formula
slope(m) = (y2 - y1) / (x2 - x1)
(1,1) x1 = 1 and y1 = 1
(4,-1) x2 = 4 and y2 = -1
now lets sub
slope(m) = (-1-1) / (4 - 1)
m = -2/3

Now we have the slope and a set of points so we will use the point slope formula
y - y1 = m(x - x1)
slope(m) = -2/3
(4,-1) x1 = 4 and y1 = -1
now lets sub
y - (-1) = -2/3(x - 4)
y + 1 = -2/3x + 8/3
y = -2/3x + 8/3 - 1
y = -2/3x + 8/3 - 3/3
y = -2/3x + 5/3 -- this is slope intercept form

now we have to turn it from slope intercept to standard form.
standard form is Ax + By = C

y = -2/3x + 5/3 (In standard form there is no fractions, therefore we have to multiply the equation by the LCD, which is 3, to get rid of the fractions.

3y = -2x + 5 (add 2x to both sides)
2x + 3y = 5 --> your equation in standard form

Answer 15

yep @texaschic101 that's exactly it.