There are two similar cones. Cone a has an altitude of 5cm and cone b has an altitude of 13cm. If cone a weighs 20lbs, how much does cone b weigh? Enter in decimal form, no rounding.

Question

anonymous · Answer

Is the volume of a cube
$$\pi \times Altitude \times R ^{3}$$

anonymous · Answer

*sorry not cube, CONE

anonymous · Answer

oh, i forgot the 1/3

anonymous · Answer

351.52 lbs

yamyam70 · Answer

Don't just give out the answers, show your work.

anonymous · Answer

no problem

anonymous · Answer

Weight = mass * g_constant
mass = density * volume
this is really a problem about finding the volume of a cone

I derived the volume as $$V = ( \pi r ^{2}h) \div 3$$

anonymous · Answer

Since cone b is 2.6 times taller than cone a, the radius of the base of cone b is 2.6 times the base radius of cone a.
using the volume formula $$R_b = 2.6 \times \sqrt{(20 lbs \times 3) \div (5cm \times \pi \times \delta \times g) }$$ where R_b is the radius at the base of cone b, delta is density and g is the gravitational constant.

Plug R_b into the volume equation and multiply it by delta and g to get your answer.

351.52 lbs

yamyam70 · Answer

:)
@amber1227  I hope you get that :) , welcome to open study! :)