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OpenStudy (primeralph):
You tell me.
OpenStudy (anonymous):
i think its false
OpenStudy (primeralph):
Show me why.
OpenStudy (anonymous):
because that would imply that the second deriv is equal to the first deriv squared and that is not always the case
OpenStudy (anonymous):
does that make sense?
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OpenStudy (primeralph):
Show me a mathematical illustration with an example to support your claim.
OpenStudy (anonymous):
like for example take 2x^3-1
the deriv is 6x^2
the second derivative 12x
and 12x does not equal (6x^2)^2
OpenStudy (primeralph):
Good job.
OpenStudy (anonymous):
thank you :)
OpenStudy (primeralph):
You did all the work. Didn't need my help.
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OpenStudy (anonymous):
that wasnt the problem tho
im having trouble with an absolute value one
OpenStudy (anonymous):
d/dx |x2 + x| = |2x + 1|
OpenStudy (anonymous):
now.... if i am thinking on the right track the left side of the equation would be x^2 +x over the absolute value of the function times the deriv which is 2x
OpenStudy (anonymous):
but i dont know how to calculate the problem.. so i might not even be on the right track
OpenStudy (primeralph):
Not really.
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OpenStudy (primeralph):
You have to set the conditions for the existence of the abs function. You need to make it piecewise.