Question

3.40 mole is theoritical yield

What is the percent yield if the actual yield from this reaction is 405g ?

Answer 1

You need to convert grams to moles, then divide theoretical yield by the actual yield, multiplying by 100 to get a percent.

Answer 2

yes how do i do that

Answer 3

how do i do this

Answer 4

canyou please show me

Answer 5

450 grams of what?

Answer 6

Consider a situation in which 235g of P4 are exposed to 272g of O2.


n Part A, you found the amount of product (3.80mol P2O5 ) formed from the given amount of phosphorus and excess oxygen. In Part B, you found the amount of product (3.40mol P2O5 ) formed from the given amount of oxygen and excess phosphorus.
Now, determine how many moles of P2O5 are produced from the given amounts of phosphorus and oxygen.

Answer 7

that was part of the question

Answer 8

Okay.. what was the 450 grams of, though? What is the chemical formula.

Answer 9

is it P2O5?

Answer 10

What is the percent yield if the actual yield from this reaction is 405g ?

Answer 11

it says if so i think it is for p205

Answer 12

Percent yield of WHAT. The way to find the number of moles is to divide grams by the molar mass, so I need to know what the 450g is so I can find the molar mass.

Answer 13

P4+5O2→2P2O5 reaction

Answer 14

if it's p2o5, then multiply p by two and o by 5, add the two. Then divide 450 g by the molar mass.

Answer 15

this is part a

What is the maximum amount in moles of P2O5 that can theoretically be made from 235g of P4 and excess oxygen?

that i got 3.80 as answer

Answer 16

Part B

What is the maximum amount in moles of P2O5 that can theoretically be made from 272g of O2 and excess phosphorus?

answer is 3.40

Answer 17

pART C

In Part A, you found the amount of product (3.80mol P2O5 ) formed from the given amount of phosphorus and excess oxygen. In Part B, you found the amount of product (3.40mol P2O5 ) formed from the given amount of oxygen and excess phosphorus.
Now, determine how many moles of P2O5 are produced from the given amounts of phosphorus and oxygen.

ANWER IS 3.40

Answer 18

part d

What is the percent yield if the actual yield from this reaction is 405g ?

Answer 19

it say if the actual yield is 405 g

Answer 20

Then follow my directions. Take P2O5, find its molar mass, and divide the 450 grams by the MM. Divide theoretical yield by actual yield, multiply by 100, and that's your percent.

Answer 21

moar mass of p205 is 141.944522

Answer 22

right

Answer 23

yes, use 141.94

Answer 24

so 405 divide by 141.94 is 2.8533

Answer 25

yes.

Answer 26

Now divide & multiply by 100 for the percentage.

Answer 27

is is .70 answer

Answer 28

2.8533/450 *100

Answer 29

is .70

Answer 30

right

Answer 31

no. sorry, had it backwards. actual yield over theoretical, then x100.
You're going to use the moles, not moles and grams. it's one or the other.

Answer 32

so 2.85/3.40 x 100

Answer 33

83.8

Answer 34

yes

Answer 35

thanks

Answer 36

mmhm.