In a loop-the-loop ride a car goes around a vertical, circular loop at a constant speed. The car has a mass m = 268 kg and moves with speed v = 16.24 m/s. The loop-the-loop has a radius of R = 10.5 m. 1) What is the magnitude of the normal force on the care when it is at the bottom of the circle? (But as the car is accelerating upward.)
What I don't understand is the centripetal force. How do we solve for the normal force?
The centripetal force is the net force towards the center of the circle. If something is travelling in a circular path, then this force = mv²/r. What are the vertical forces acting on the cart when it's at the bottom of the loop-the-loop?
Oh, so when youre dealing with circles the force=[mv^2\]/R. Cool. Now, since the cart is at the bottom, the normal force is perpendicular to the car. Correct?
Normal force is perpendicular to the edge of the circle (points towards the center)
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