The perimeter of a rectangular ranch is 400 m. Find the dimensions of the ranch that will contain the greatest area.
Wow every time i go to answer a question that i am incapable of answering you answer for me :)
so could be 50+50+100+100
could also be all 75
I am horrible at this stuff even though it looks very simple
500 or 150
do the 500 one
so 50+50+100+100
I know it's just a simple question but I just don't know how to start it.
it's an optimization problem
use the derivative to find the local maximum which in this case, the largest area
uhmmm, how? i don't know that @11calcBC
set x = length and y = width, u know that 2x + 2y = 400, so x =200 - y
implicit differentiation...
2(200 - y) + 2y = 400 400 - 2y + 2y = 400 400 = 400
is that right ?
well...it's right but plugging it in isn't solving it lol
u plug 200 - y into the area, so u get A(x) = (200-y)y
which you simplify to 200y - y^2
take the derivative of that, which is 200 - 2y
set that equal to 0, get ur critical point, which is 100 for y when you solve for it. remember to find the x value, which is 2x + 2(100) = 400, which is also equal to 100. also note that a number is the greatest when it's two values are the same
ur maximum area will then be 100 x 100 or 10,000
thank you so much for letting me understand and for helping me out with this :) @11calcBC :)
my pleasure :D
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