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Calculus1 7 Online
OpenStudy (anonymous):

find dy/dx of sinxy using implicit differentiation

OpenStudy (anonymous):

you could simply use the chain rule where you can let xy=u then differenciate xy apart(implicitely) and sin u apart.After which you substitute back u=xy in the final result which is y+x dy/dx and cos u and we have cos xy from u=xy which gives us (y+xdy/dx)cosxy

OpenStudy (anonymous):

thank you!

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