Question

(4^x)/(4^x-1)?

Answer 1

\[\Large \frac{4^x}{4^x-1}\]We need to simplify or what? :)

Answer 2

Oops, is the -1 in the exponent?

Answer 3

yes simplify, and yes -1 is an exponent

Answer 4

\[\Large \frac{4^x}{4^{x-1}}\]Ah ok :)

Answer 5

i am getting 4^-1, which i assume = 0.25?

Answer 6

When we divide exponentials of similar bases, we `subtract` the exponents.\[\Large \frac{4^x}{4^{x-1}}\quad=\quad 4^{x-(x-1)}\quad=\quad?\]
Might want to put brackets like I did there, so you don't forget to distribute the negative ^^

Answer 7

4^2x-x-x+1 = 4^1 = 4?

Answer 8

\[\frac{4^x}{4^{x-1}}=\frac{\cancel{4^x}}{\cancel{4^{x}}4^{-1}}\]

Answer 9

Yes, good rube :)
Yah amistre has another clever way of doing it there also ^

Answer 10

Wait where did the 2x come from? XD

Answer 11

\[\Large 4^{x-(x-1)}\quad=\quad 4^{x-x+1}\]

Answer 12

i multiplied x-(x-1) but i guess that was not right....
how did you get 4^x-x+1 from 4^x-(x-1)

Answer 13

I distributed the negative sign to each term in the brackets.

Answer 14

\[\LARGE x-1\cdot(x-1)\quad=\quad x-1x+1\]We're just distributing the -1 to each term in the brackets.
Confused about that? :o
The other x isn't multiplying the brackets.

Answer 15

I understand now, i forgot that step when u have a negative outside the brackets you change the signs inside the brackets.
Thanks!

Answer 16

cool \c:/