Question

Please help
A 3.3 kg mass with an initial velocity of
v1 = aˆi, where a = 3.47 m/s collides with
and sticks to a 0.989 kg mass with an initial
velocity of v1 = bˆj, where b = −4.8 m/s.
Find the final speed of the composite mass.
Answer in units of m/s

Answer 1

it is a perfectly inelastic collision..
linear momentum will be conserved..
let the x component of the final velocity is \(v _{x}\) and the y component of that is \(v _{y}\)
in x direction..\[m _{1}*a+m _{2}*0=(m _{1}+m _{2})*v _{x}\]
and in y direction..\[m _{1}*0+m _{2}*b=(m _{1}+m _{2})*v _{y}\]
now the final velocity will be \[\large{v=\sqrt{v ^{2}_{x}+v ^{2}_{y}}}\]

Answer 2

I cant see the equations :/

Answer 3

I've gotten the answer of about 3 and it is wrong

Answer 4

Also I got 1.56