Question

Find the nth term for the following sequences (with index starting at n=1) SEE BELOW!

Answer 1

(a) 8, -9/4, 10/9
(b)6/5, 10/9, 14/13

Answer 2

I have that the difference between the denominators for A is 1, 3, 5. So i'm assuming the denominator follows the odd order, but thats all i have

Answer 3

I know I generally say something is odd by (2K+1), but that gives me a first term of 3, if k starts at 1

Answer 4

so far for A i have \[(-1)^{n+1}\frac{ n+7 }{ ? }\]

Answer 5

the first part compensates for the alternating sign, and the numerator seems to fit. I am just not sure how to represent the denominators

Answer 6

Try this for part a,

\(\displaystyle(-1)^{n+1}(\frac{n+7}{n^2})\)

Answer 7

omg wow, duh! thanks

Answer 8

I believe that should get you the denominators that you are looking for with this sequence.
Do you have any thoughts for part b?

Answer 9

well for the denominators there is a difference of 4 for each one

Answer 10

and for the denominator as well

Answer 11

but i'm stuck from there

Answer 12

I am drawing a bit of a blank.... I can almost get one to work, but.... I am a bit rusty with these :P

Answer 13

No problem. I think I will head to my teacher's office tomorrow. Thanks a bunch though!

Answer 14

No problem, @amistre might be able to help. He is more well rounded than me.

Answer 15

@amistre64 forgot the 64.....

Answer 16

thanks i'll do that