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Physics 17 Online
OpenStudy (anonymous):

http://session.masteringphysics.com/problemAsset/1169458/2/jfk.Figure.23.P50.jpg The 10 Ω resistor in the figure is dissipating 40 W of power. (Figure 1) How much power is the 20Ω resistor dissipating?

OpenStudy (anonymous):

P = V^2/R So, since it's parallel the voltage is the same. V^2 = P * R = 40W * 10Ω = 400 Power in 20Ω = V^2/R = 400/20 = 20W

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