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OpenStudy (anonymous):
burgular alarm system has six fail-safe components. the probability of each failing is 0.05. Find these probabilities a)Exactly three will fail b) Fewer than two will fail. c) None will fail. d) Compare the answers from a,b,and c and explain why the results are reasonable
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OpenStudy (anonymous):
So are these independent fail-safes, or are they sequential where one must die before the others have a chance to work?
OpenStudy (anonymous):
If they're independent then we have a binomial distribution.
OpenStudy (anonymous):
\[ X\sim B(n=6,p=0.5)\implies P(X=k) = \binom 6k(0.05)^k(1-0.05)^{6-k} \]
OpenStudy (anonymous):
a) \(Pr(X=3)\) b) \(\Pr(X<3) =Pr(X=0)+Pr(X=1) \) c) \(\Pr(X=0)\)
OpenStudy (anonymous):
Plug and chug.
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OpenStudy (anonymous):
thanks so much for your help
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