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Mathematics 13 Online
OpenStudy (anonymous):

Which equation best represents the graph shown? y=-(x+1)^2-1 y=(x-1)^2 y=(x+1)^2 y=-(x-1)^2+1

OpenStudy (anonymous):

OpenStudy (jdoe0001):

\(\bf y = A ( Bx + C )^2 + D\) C = horizontal shift, C > 0, to the left, C < 0, to the right

OpenStudy (anonymous):

would it be A?

OpenStudy (anonymous):

@Nurali

OpenStudy (freethinker):

I am going to pick up from where joe left off

OpenStudy (freethinker):

I am going to use a slightly different letters, but they essentially mean the same. It is just something I've been using

OpenStudy (freethinker):

the standard form of a parabola is in the equation \[y=a(x-h)^2 + k\] where a ≠ 0 your vertex - that is the highest or lowest point is (h, k) your a determines how far apart are your x-intercepts when a is positive then it looks like a cup or bowl. when it is negative, it looks like a hill

OpenStudy (anonymous):

SO, it's C

OpenStudy (freethinker):

\[y = a(x-h)^2 + k\] h = -(-1 ) k = 1 your vertex is at (1,1)

OpenStudy (freethinker):

sorry vertex is at (1, 0)

OpenStudy (freethinker):

k = 0

OpenStudy (freethinker):

you are correct it is C

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