Which equation best represents the graph shown?
y=-(x+1)^2-1
y=(x-1)^2
y=(x+1)^2
y=-(x-1)^2+1
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OpenStudy (anonymous):
OpenStudy (jdoe0001):
\(\bf y = A ( Bx + C )^2 + D\)
C = horizontal shift, C > 0, to the left, C < 0, to the right
OpenStudy (anonymous):
would it be A?
OpenStudy (anonymous):
@Nurali
OpenStudy (freethinker):
I am going to pick up from where joe left off
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OpenStudy (freethinker):
I am going to use a slightly different letters, but they essentially mean the same. It is just something I've been using
OpenStudy (freethinker):
the standard form of a parabola is in the equation
\[y=a(x-h)^2 + k\] where a ≠ 0
your vertex - that is the highest or lowest point is (h, k)
your a determines how far apart are your x-intercepts
when a is positive then it looks like a cup or bowl. when it is negative, it looks like a hill
OpenStudy (anonymous):
SO, it's C
OpenStudy (freethinker):
\[y = a(x-h)^2 + k\]
h = -(-1 )
k = 1
your vertex is at (1,1)
OpenStudy (freethinker):
sorry vertex is at
(1, 0)
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