Question

Correct Me 4 Medal !!! ^o^

Answer 1

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Answer 2

Consider the line that passes through the point (3, -6) and has a slope of 4.

Part 1: Write the equation of this line using point-slope form. (2 points)
Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. (2 points)
Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work. (2 points)

Answer 3

1.) y=4x-6

2.) y-6=4(x-3)
y-6=4x-12
+6 +6
----------------
[ y = 4x - 6 ]

3.) 4x + y = -6
4x + 0 = -6

Answer 4

3.) 4x + y = -6
4x + 0 = -6
4x = -6
x = -1.5

4x + y = -6
0 + y = -6
y = -6

Answer 5

how did you get Part 1?

Answer 6

y-6=4(x-3) <-- by solving that :3

Answer 7

hmm let's solve that then...
\(\bf (3,-6)\qquad m=4\qquad y-y_1=m(x-x_1)\\ \quad \\
y -(-6)= 4(x - (3))\implies y+6=4x-12\implies y = 4x-18\)

Answer 8

oooooohh ! ok I see what I did wrong but the others are correct ?

Answer 9

\( \begin{array}{llll}
&point-slope form&slope-intercept form\\
y -(-6)= 4(x - (3))\implies &y+6=4x-12\implies &y = 4x-18
\end{array}\)

Answer 10

standard form would be 4x-y-18 = 0 more or less

Answer 11

there are several acceptable standard forms... so 4x-y = 18 may also work http://www.mathsisfun.com/algebra/standard-form.html